I was wandering what the graph of
z(x,y) = [y^(ix)-y^(-ix)]/2
looks like.
I know for z(x,e) the graph is sin(x) and I think z(x,0) is 1 for all x and z(x,1) is 0 for all x. But I don't know how to find it for all y. The problem is the imaginary numbers. If anyone knows how to create this graph just let me know.
Saturday, December 25, 2004
A ?
Posted by paul at 11:05 AM
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